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Language Mercur

Date:07/05/05
Author:Johan Lindemann
URL:n/a
Comments:0
Info:http://www.mercur.com
Score: (2.00 in 3 votes)
def dfB=99
newtab; coln Song; Song string " "; &tab norownames
Song=substring((dfB-rcum(transp((0,1,0):*(dfB-1),0,1))) 1 8)+" bottle" when transp((1,1,0):*dfB)
Song=Song+"s" when (Song <> "1 b*") and (Song <> 0/0)
Song="no more bottles" when Song equal "0 b*"
Song=Song+" of beer on the wall, "+Song+" of beer." when rshift(1 Song) equal 0/0
Song="Take one down, pass it around, "+Song+" of beer on the wall." when rshift(-1 Song) equal 0/0
textf('dfB'+" bottles of beer") title 99
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