Language TeX/LaTeX
Date: | 04/20/05 |
Author: | Craig J. Copi |
URL: | n/a |
Comments: | 4 |
Info: | n/a |
Score: | (2.95 in 119 votes) |
%% TeX/LaTeX version of 99 bottles of Beer %% %% Craig J Copi - copi@oddjob.uchicago.edu %% \parindent=0pt \newcount\beercurr \def\beer#1{\beercurr=#1\let\next=\removebeer\removebeer} \def\removebeer{ \ifnum\beercurr>1 \the\beercurr\ bottles of beer on the wall,\par \the\beercurr\ bottles of beer,\par take one down, pass it around,\par \advance\beercurr by -1 \the\beercurr\ bottle\ifnum1<\beercurr{s}\fi\ of beer on the wall.\par \vskip 2ex\relax \else 1 bottle of beer on the wall,\par 1 bottle of beer,\par take one down, pass it around,\par no bottles of beer on the wall.\par \vskip .5ex Time to buy some more beer\ldots. \let\next=\relax \fi \next} \beer{99}
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Comments
Volker Kuhlmann said on 05/16/05 02:21:49
This works in neither TeX nor LaTeX. LaTeX just spits a "missing \begin{document}" and calls it quits. TeX doesn't create the last page of output because the whole document is missing termination with \bye.
Does anyone ever test the programs posted here?
Stefan Scheler said on 05/16/05 19:44:36
Well, this is material from Tim's first version of the site. This code is ~10 years old. So I assume it worked with a previous version of tex. Try this one http://www.99-bottles-of-beer.net/language-latex2e-354.html instead.
And dude, of course we don't have to time to check all this old stuff. We do this in our free time.
Kiyoshi Akima said on 04/25/06 03:51:29
It works fine in TeX if you change the \ldots toward the bottom to \dots
Johannes said on 02/02/10 14:08:51
The assumption that it will work with an earlier version of TeX is most probably wrong. TeX is a *very* stable language, virtually unchanged since 1978 a.f.a.i.k.
BTW, anything free comes with no guarantee.