99 Bottles of Beer

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Language Condit

Date:	12/21/10
Author:	Marinus Oosters
URL:	n/a
Comments:	0
Info:	http://equ.in/ox/comp/obfuscated/condit/
Score:	(3.20 in 5 votes)

when a=0                         then set a=1 set b=99 set r=1 set O=""
when (r=1 or r=2 or r=4) and b>0 then put b set O=""
when (r=1 or r=2 or r=4) and b=0 then set O="No more "
when (r=1 or r=2 or r=4) and b<0 then set O="99 "
when r=1 or r=2 or r=4           then set O=O+"bottle"
when r>0 and b<1 or b>1          then set O=O+"s"
when r=1 or r=2 or r=4           then set O=O+" of beer"
when r=1 or r=4                  then set O=O+" on the wall"
when r=3 and b>0                 then set O="Take one down and pass it around"
when r=3 and b<1                 then set O="Go to the store and buy some more"
when r>0 and r<4                 then set O=O+",\n"
when r=4                         then set O=O+".\n\n"
when r=3                         then set b=b-1
when r>0                         then set r=r+1 put O set O=""
when r>4 and b<0                 then set r=0
when r>4                         then set r=1

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